Well, now that I think about it a little more, I’m not so sure. NO argument @CAP777 – but You MUST BE CORRECT because you came up with the correct answer!!!!!. And I have to use parts of your logic to get the right answer myself, so unfortunately that MUST mean I didn’t have it exactly right before. ANYHOW – like they say “math is fun”
Understanding that there are multiple ways get to Denmark, is this a simpler WAY to look at it?
We “KNOW” that the OP’s vehicle moves forward 1.83 ‘meters’ per tire revolution.
At a given RPM (say for example 1600 RPM), with an overall gear ratio through trans & differential of 2.333 —:
means the tire should be turning 1600/2.33 revolutions “PER MINUTE”, or (1600/2.33) = 686.695278 tire revs per minute through the cumulative gear rations per OP’s post. With a tire circumference of 1.83 meters, that would move the vehicle along 1256.6523 meters per minute. Correct?
THEN: we should be able to simply multiply that by 60 to get ‘meters per hour’. Then divide by 1000 for kph: that = 75.399 kph (like you said), or
meters per hour = ([OC]/2.33)*1.83*60
As is usually the case there are several ways to skin a cat. Using my original (though perhaps lame) acronyms, could we correctly express this for a Torque Formula as:
RPM_to_kph Formula = ((([OC]/(ODr*Diffr))*TireCir)*60)/1000
Where:
TireCir is Tire circumference in meters
ODr is Gear ratio, in this case Over Drive
Diffr is Differential ratio
Of course if the Units are specified in ‘kph’ in a Custom PID, Torque should convert it to MPH if that option is set in General Settings.
Whatcha think?
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EDIT: TireCir & formula brackets
