??Interesting. Another good anti-dementia exercise for old farts like me.

It’s actually pretty easy – by just creating a virtual PID (one with MODE/PID# blank), IF:
o- you don’t care about it being wrong in gears below HI & OD
o- or you don’t care about Torque Converter slip if automatic.
o- your vehicle is standard transmission or has locking TC.
o- you keep your drive tires inflated the same.
o- you know the circumference of the drive tires in ft (Tdia-ft)
o- you know the transmission overdrive transfer ratio (ODr)
o- you know the differential gear ratio (Diffr)
o- you know Torque is able to read standard [RPM PID] [0C]

Then you would simply create a new custom pid (a ‘virtual’ PID) similar to

MODE/PID: blank
Long Name: My RPMSPEED
Short Name: RPMSpeed
Min – Max as appropriate
Units: MPH
Formula: ([0C]/60)*(1/ODr)*(1/Diffr)*(5280/Tdia-ft)
Header: Auto
Start Stop Diagnostic: blank

Then you could add a gauge of your choice and select “My RPMSPEED” from your scroll list of pids.

IF you have/can find a PID for GEAR (and knew each gear ratio), I could structure a formula that would work accurately by summing results for each gear while negating formula results for all gears that are not currently true.

But it seems there are lots of variables that would make it result in a meaningless number.

————–

54371019

=======================4/21/17
EDIT: To avoid confusion to future readers, after my errors / mistakes pointed out by @Capp777 were made in following discussions, the correct formula was determined to be:

Formula: ((([OC]/(0.83*2.813))*1.83)*60)/1000 for the OD gear ratio, differential ratio, and tire circumference of this vehicle – in 6th gear.

1. Leaving the Mode/PID blank makes the whole PID entry work like a ‘virtual’ PID from the PCM – or another way to look at is like a ‘memory variable’ in Torque that shows up in your PID list by the Long Name that you assigned it. [OD] and [OC] are the ‘standard’ hexadecimal PID numbers for VSS (Vehicle Speed) and RPM respectively. Using ANY valid PID number in brackets that way in a formula will return the value from that PID (as per its formula) and use it in any other formula or PID.

I note that the link you provided is calculating the gear from RPM. That would be much easier because the resolution / accuracy could be quiet sloppy without the ‘integer’ (gear) changing much. My 2004 F150 presents GEAR as an integer number at PID # 11B3, but I’m sure that wouldn’t be the same on your BMW.

2. (Tdia-ft) is just the acronym that I chose to mean Tire diameter in feet – because I know there are 5280 feet in a mile and that made it straight forward. I have no idea what the diameter would be of 245/40/17 tires (metric or SAE) but surely that’s readily available – BUT – that would ‘skew’ some depending on inflation pressure, IDK.

The formula, like everything else metric, would be cleaner in metrics. Just put the distance and tire radius in meters and change the PID Units to KPH. That would also cause Torque to treat the speed reading in accordance with the Settings parameters for Kilometers Per Hour or Miles Per Hour as appropriate.

You correctly interpreted te Acronyms for (ODr) and (Diffr). With the gear Ratios you’ve got – looks like you are there.

————–

54371019

Thanks @Capp777 for catching my goof. Certainly its circumference. I guess if he can’t find circumference in the tire specs, we could throw ‘pi’ into the formula. But for sure in the end we gotta’ know how far the car travels with one revolution.

—————–

54371019

Quote from userM on April 17, 2017
…
I can’t find out
the transmission overdrive transfer ratio (ODr)
the differential gear ratio (Diffr)
if someone can help is very welcome

[end quote]

—————–

Isn’t the answer in the data you provided in ‘post # 3’ above?

Looks to me like (Diffr) is 2.81 to 1.

And the ‘final ratio’ – through the differential – is listed in parenthesis for each gear.

If I multiply third gear ratio 1.659 X axle ratio 2.81, I get (4.66179)

Then Sixth gear (ODr) should be 0.83 x 2.81 or (2.3323)

————–

54371019

NOTE that @Cap777 correctly pointed out that in my haste, I mistakenly was thinking (and chose an acronym) referring to “Diameter” (Tdia-ft) when it should properly be “Circumference”. Not that the acronym makes any difference – but the measurement should be the distance all the way around the tread of the tire – in either feet, or meters/centimeters depending on what distance / hour you are trying to arrive at.

It is an interesting concept. Math in fun. Help me try to convince @piemmm to implement Boolean math in the math routine, and if you can come up with a ‘gear’ pid, I will work out a formula for you that will produce the same speed result, no matter what gear you are in.

Good luck

————–

54371019

Quote from userM on April 20, 2017
question.. I can’t understand -ft in formula.

([0C]/60)*(1/2,3323)*(1/2,813)*(5280/Tdia-ft)

lets say I want kilometers per hour = 1000 meters
lest also say that tdia=1meter
so the last part should be
*(1000/1 – ft?) what meters-foot should here?

End Quote.

The formula given is in Feet which could be converted
by (meters in a mile/tire circumference in meters).

To me the [0C] rpms should be multiplied by 60 to get
rounds per hour. Would be nice to know your tire
circumference to play with the numbers.

5280 feet in a mile
5280 * 0.3048 equals meters per mile
5280 * 0.0003048 equals Kilometers per mile
miles per hour * 1.609344 equals Kilometers per hour

F-150Torqued:

Could you confirm the divide by 60? It
seems more logical to me that you need
to know the rounds per hour (*60).

Quote from userM on April 20, 2017
so the Circumference of 1 tire is 1,83 meters
and the formula should read

([0C]/60)*(1/2,3323)*(1/2,813)*(1000/1,83)
I don’t know if we could tell that it equals with
([0C]/60)*83,2903651

Now, I don’t know what can I do with this virtual pid )

If I make it in the settings it turns blue but I can not bring it to torque dials.. :/

End Quote.

[0C] equals revolutions per minute exit engine
([0C]*60) equals revolutions per hour exit engine
([0C]*60)*(1/0.83) equals revolutions per hour exit trans
([0C]*60)*(1/0.83)*(1/2.813) equals revolutions per hour exit diff
([0C]*60)*(1/0.83)*(1/2.813)*tire circumference equals meters per hour
([0C]*60)*(1/0.83)*(1/2.813)*(tire circumference/1000) equals kph
This assumes tire circumference is in meters.

([0C]*60)*(1/0.83)*(1/2.813)*(tire circumference/5280) equals mph
This assumes tire circumference is in feet.

Am I wrong with my thinking?

So if [0C] equals 1600 rpm…

(1600*60)*(1/0.83)*(1/2.813)*(1.83/1000) = 75.244 kph
(1600*60)*(1/0.83)*(1/2.813)*(6.00/5280) = 46.755 mph

in 6th gear.

(1600*60)*(1/0.83)*(1/2.813)*(1.83/1000) = [0D]
(1600*60)*(1/0.83)*(1/2.813)*1.83 = [0D]*1000
(1600*60)*(1/0.83)*1.83 = [0D]*1000*2.813
(1/0.83) = ([0D]*2813)/(1600*60*1.83)
1 = ([0D]*2813)/(1600*60*1.83)*0.83
0.83 = 1*(1600*60*1.83)/([0D]*2813)
0.83 = 1*([0C]*60*1.83)/([0D]*2813)

Gear Ratio = ([0C]*60*TireCir)/([0D]*2813)

0.83 = (1600*60*1.83)/(75.244*2813)

Edited.

Works for me. Math is fun when
you are trying something new.

I could have condensed the equations
but I was trying to show each step to
reaching the final result based upon my
thinking of *60 vs /60.

Hopefully the OP can follow along and
this answers his original quest.

If your vehicle supports …

[0C] Engine rpm
[0D] Vehicle Speed in kph
TireCir Tire Circumference in meters

GearRatio = ([0C]*60*TireCir)/([0D]*2813)

0.83 = (1600*60*1.83)/(75.244*2813)

To my knowledge there is no way to look
up a ratio to gear.